radicals

Solve for $x$ from the following equations

1. $\sqrt{3 - x} + \sqrt{4 - 2x} = \sqrt{3 - 3x}$
    
2. $\sqrt{\dfrac{2x + 4}{x - 5}} + 8\sqrt{\dfrac{x - 5}{2x + 4}} = 6$

Problem
Evaluate $\displaystyle \int \left( \sqrt{x} + x\sqrt{x} + \dfrac{1}{\sqrt{x}} \right) \, dx$