poisson's ratio

Solution to Problem 225 Biaxial Deformation

Problem 225
A welded steel cylindrical drum made of a 10-mm plate has an internal diameter of 1.20 m. Compute the change in diameter that would be caused by an internal pressure of 1.5 MPa. Assume that Poisson's ratio is 0.30 and E = 200 GPa.
 

Shearing Deformation

Shearing Deformation
Shearing forces cause shearing deformation. An element subject to shear does not change in length but undergoes a change in shape.
 

shearing-deformation.jpg

 

The change in angle at the corner of an original rectangular element is called the shear strain and is expressed as
 

$\gamma = \dfrac{\delta_s}{L}$

 

The ratio of the shear stress τ and the shear strain γ is called the modulus of elasticity in shear or modulus of rigidity and is denoted as G, in MPa.
 

$G = \dfrac{\tau}{\gamma}$

 

The relationship between the shearing deformation and the applied shearing force is
 

$\delta_s = \dfrac{VL}{A_s G} = \dfrac{\tau L}{G}$

 

where V is the shearing force acting over an area As.
 

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