# perimeter

## Perimeter of the curve r = 4(1 + sin theta) by integration

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## 10 Swimming pool in the shape of two intersecting circles

**Situation**

A swimming pool is shaped from two intersecting circles 9 m in radius with their centers 9 m apart.

Part 1: What is the area common to the two circles?

A. 85.2 m^{2}

B. 63.7 m^{2}

C. 128.7 m^{2}

D. 99.5 m^{2}

Part 2: What is the total water surface area?

A. 409.4 m^{2}

B. 524.3 m^{2}

C. 387.3 m^{2}

D. 427.5 m^{2}

Part 3: What is the perimeter of the pool, in meters?

A. 63.5 m

B. 75.4 m

C. 82.4 m

D. 96.3 m

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## Common Quadrilaterals

**Square**

Area, $A = a^2$

Perimeter, $P = 4a$

Diagonal, $d = a\sqrt{2}$

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