Given that w varies directly as the product of x and y and inversely as the square of z and that w = 4 when x = 2, y = 6, and z = 3. Find the value of w when x = 1, y = 4, and z = 2. A. 2 C. 4 B. 3 D. 5 Solution Click here to… Jhun Vert Sat, 07/13/2024 - 19:25 Solution Click here to expand or collapse this section $w = \dfrac{kxy}{z^2}$ $4 = \dfrac{k(2)(6)}{3^2}$ $k = 3$ $w = \dfrac{3xy}{z^2}$ $w = \dfrac{3(1)(4)}{2^2}$ $w = 3$ Log in or register to post comments Log in or register to post comments
Solution Click here to… Jhun Vert Sat, 07/13/2024 - 19:25 Solution Click here to expand or collapse this section $w = \dfrac{kxy}{z^2}$ $4 = \dfrac{k(2)(6)}{3^2}$ $k = 3$ $w = \dfrac{3xy}{z^2}$ $w = \dfrac{3(1)(4)}{2^2}$ $w = 3$ Log in or register to post comments
Solution Click here to…