Find the area bounded by the y-axis and the lines y = 6x - 1 and y = 0.25x + 3.

$6x - 1 = \frac{1}{4}x + 3$

$x = \frac{16}{23}$
 

$A = \frac{1}{2}(4)(\frac{16}{23})$

$A = \frac{32}{23} ~ \text{unit}^2$