The sum of the interior angles of a polygon of n sides is four times the sum of its exterior angles. Find the value of n. The sum of the interior angles of a polygon of n sides is four times the sum of its exterior angles. Find the value of n. A. 12 C. 15 B. 8 D. 10 Log in or register to post comments Solution Click here to… Jhun Vert Sat, 06/29/2024 - 15:53 Solution Click here to expand or collapse this section $\sum \text{interior angles} = 4 \times \sum \text{exterior angles}$ $180^\circ (n - 2) = 4(360^\circ)$ $n = 10$ Log in or register to post comments
Solution Click here to… Jhun Vert Sat, 06/29/2024 - 15:53 Solution Click here to expand or collapse this section $\sum \text{interior angles} = 4 \times \sum \text{exterior angles}$ $180^\circ (n - 2) = 4(360^\circ)$ $n = 10$ Log in or register to post comments
Solution Click here to…