Find the value of x if $x = \dfrac{1 + \tan^2 \phi}{\tan \phi \, \csc^2 \phi}$.

$\begin{align} x & = \dfrac{1 + \tan^2 \phi}{\tan \phi \, \csc^2 \phi} \\ \\ & = \dfrac{\sec^2 \phi}{\tan \phi \, \csc^2 \phi} \\ \\ & = \dfrac{\dfrac{1}{\cos^2 \phi}}{\dfrac{\sin \phi}{\cos \phi} \cdot \dfrac{1}{ \, \sin^2 \phi}} \\ \\ & = \dfrac{\dfrac{1}{\cos^2 \phi}}{\dfrac{1}{\sin \phi \, \cos \phi}} \\ \\ & = \dfrac{\dfrac{1}{\cos \phi}}{\dfrac{1}{\sin \phi}} \\ \\ & = \dfrac{\sin \phi}{\cos \phi} \\ \\ & = \tan \phi \end{align}$