Find k so that x + 6 is a factor of x^4 + 4x^3 - 21x^2 + kx + 108. Find k so that x + 6 is a factor of x4 + 4x3 - 21x2 + kx + 108. A. -36 C. +32 B. -24 D. +48 Log in or register to post comments Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:59 Solution Click here to expand or collapse this section f(x)=x4+4x3−21x2+kx+108 (x−r)=x+6 r=−6 Factor Theorem If (x−r) is a factor of f(x) then f(r)=0 f(−6)=0 (−6)4+4(−6)3−21(−6)2+k(−6)+108=0 1296−864−756−6k+108=0 6k=−216 k=−36 Log in or register to post comments
Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:59 Solution Click here to expand or collapse this section f(x)=x4+4x3−21x2+kx+108 (x−r)=x+6 r=−6 Factor Theorem If (x−r) is a factor of f(x) then f(r)=0 f(−6)=0 (−6)4+4(−6)3−21(−6)2+k(−6)+108=0 1296−864−756−6k+108=0 6k=−216 k=−36 Log in or register to post comments
Solution Click here to…