Shear Stress

Forces parallel to the area resisting the force cause shearing stress. It differs to tensile and compressive stresses, which are caused by forces perpendicular to the area on which they act. Shearing stress is also known as tangential stress.
 

$\tau = \dfrac{V}{A}$

 

where V is the resultant shearing force which passes through the centroid of the area A being sheared.
 

Normal Stresses

Stress is defined as the strength of a material per unit area or unit strength. It is the force on a member divided by area, which carries the force, formerly express in psi, now in N/mm2 or MPa.
 

$\sigma = \dfrac{P}{A}$

 

where P is the applied normal load in Newton and A is the area in mm2. The maximum stress in tension or compression occurs over a section normal to the load.
 

Strength of Materials

Reviewer in Strength of Materials

This page is the portal of the Reviewer in Strength of Materials. You can find here some basic theories and principles. Most of the content however for this online reviewer is solution to problems. You can find here a compiled step-by-step solution to problems in Strength of Materials. Feel free to explore the pages by selecting the topics tabulated below or browse it by chapters given as links below the tabulated data.
 

Solution to Problem 114 Normal Stress

Problem 114
The homogeneous bar ABCD shown in Fig. P-114 is supported by a cable that runs from A to B around the smooth peg at E, a vertical cable at C, and a smooth inclined surface at D. Determine the mass of the heaviest bar that can be supported if the stress in each cable is limited to 100 MPa. The area of the cable AB is 250 mm2 and that of the cable at C is 300 mm2.