If sec 2A = 1 / sin 13A, determine the value of A in degrees. If sec 2A = 1 / sin 13A, determine the value of A in degrees. A. 7 C. 3 B. 6 D. 5 Solution Click here to… Jhun Vert Thu, 07/04/2024 - 18:56 Solution Click here to expand or collapse this section sec2A=1sin13A sec2A=csc13A sec2A=sec(90∘−13A) Hence, 2A=90∘−13A 15A=90∘ A=6∘ You can also do trial and error using the choices sec2A=1sin13A 1cos2A=1sin13A Try A = 3°: 1cos6∘≠1sin39∘ ← not ok Try A = 5°: 1cos10∘≠1sin65∘ ← not ok Try A = 6°: 1cos12∘=1sin78∘ ← ok! Try A = 7°: 1cos14∘≠1sin91∘ ← not ok Answer: A = 6° Log in or register to post comments Log in or register to post comments
Solution Click here to… Jhun Vert Thu, 07/04/2024 - 18:56 Solution Click here to expand or collapse this section sec2A=1sin13A sec2A=csc13A sec2A=sec(90∘−13A) Hence, 2A=90∘−13A 15A=90∘ A=6∘ You can also do trial and error using the choices sec2A=1sin13A 1cos2A=1sin13A Try A = 3°: 1cos6∘≠1sin39∘ ← not ok Try A = 5°: 1cos10∘≠1sin65∘ ← not ok Try A = 6°: 1cos12∘=1sin78∘ ← ok! Try A = 7°: 1cos14∘≠1sin91∘ ← not ok Answer: A = 6° Log in or register to post comments
Solution Click here to…