An equilateral triangle has an altitude of $5\sqrt{3}$ cm long. Find its area. An equilateral triangle has an altitude of $5\sqrt{3}$ cm long. Find its area. A. $\frac{5}{4}\sqrt{3} ~ \text{cm}^2$ C. $25\sqrt{3} ~ \text{cm}^2$ B. $100\sqrt{3} ~ \text{cm}^2$ D. $50\sqrt{3} ~ \text{cm}^2$ Log in or register to post comments Solution Click here to… Jhun Vert Thu, 07/04/2024 - 17:28 Solution Click here to expand or collapse this section $\tan 60^\circ = \dfrac{5\sqrt{3}}{b/2}$ $b = 10 ~ \text{cm}$ $A = \frac{1}{2}(10)(5\sqrt{3})$ $A = 25\sqrt{3} ~ \text{cm}^2$ Log in or register to post comments
Solution Click here to… Jhun Vert Thu, 07/04/2024 - 17:28 Solution Click here to expand or collapse this section $\tan 60^\circ = \dfrac{5\sqrt{3}}{b/2}$ $b = 10 ~ \text{cm}$ $A = \frac{1}{2}(10)(5\sqrt{3})$ $A = 25\sqrt{3} ~ \text{cm}^2$ Log in or register to post comments
Solution Click here to…