Find the area of the sector inside the square ABCD. Find the area of the sector inside the square ABCD. Dimensions shown are in centimeter. A. 52.36 cm2 C. 48.32 cm2 B. 64.36 cm2 D. 32.94 cm2 Log in or register to post comments <strong>Solution</strong… Jhun Vert Wed, 06/12/2024 - 20:30 Solution Click here to expand or collapse this section $\cos \alpha = 5/10$ $\alpha = 60^\circ$ $\begin{align} \theta & = 180^\circ - 2\alpha \\ \\ & = 180^\circ - 2(60^\circ) \\ \\ & = 60^\circ \end{align}$ $\begin{align} A & = \dfrac{\pi r^2 \theta_{deg}}{360^\circ} \\ \\ & = \dfrac{\pi(10^2)(60^\circ)}{360^\circ} \\ \\ & = 52.36 ~ \text{cm}^2 \end{align}$ Log in or register to post comments
<strong>Solution</strong… Jhun Vert Wed, 06/12/2024 - 20:30 Solution Click here to expand or collapse this section $\cos \alpha = 5/10$ $\alpha = 60^\circ$ $\begin{align} \theta & = 180^\circ - 2\alpha \\ \\ & = 180^\circ - 2(60^\circ) \\ \\ & = 60^\circ \end{align}$ $\begin{align} A & = \dfrac{\pi r^2 \theta_{deg}}{360^\circ} \\ \\ & = \dfrac{\pi(10^2)(60^\circ)}{360^\circ} \\ \\ & = 52.36 ~ \text{cm}^2 \end{align}$ Log in or register to post comments
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