Which of the following is equal to $\dfrac{\sin \theta}{1 + \cos \theta}$.

$\begin{align}
\dfrac{\sin \theta}{1 + \cos \theta} & = \dfrac{\sin \theta}{1 + \cos \theta} \times \dfrac{1 - \cos \theta}{1 - \cos \theta} \\
\\
& = \dfrac{\sin \theta (1 - \cos \theta)}{1 - \cos^2 \theta} \\
\\
& = \dfrac{\sin \theta (1 - \cos \theta)}{\sin^2 \theta} \\
\\
& = \dfrac{1 - \cos \theta}{\sin \theta}
\end{align}$