Decompose the given term into partial fraction and compute for the value of A: (7x + 17) / (x + 3)^2

$\dfrac{7x + 17}{(x + 3)^2} = \dfrac{A}{x + 3} + \dfrac{B}{(x + 3)^2}$

$7x + 17 = A(x + 3) + B$
 

Set x = -3
$7(-3) + 17 = A(-3 + 3) + B$

$B = -4$
 

Equate the constant terms
$17 = 3A + B$

$17 = 3A - 4$

$A = 7$