Decompose the given term into partial fraction and compute for the value of A: (7x + 17) / (x + 3)^2 Decompose the given term into partial fraction and compute for the value of A. $$\dfrac{7x + 17}{(x + 3)^2}$$ A. 5 C. 7 B. 6 D. 8 Log in or register to post comments Solution Click here to… Jhun Vert Fri, 06/07/2024 - 19:05 Solution Click here to expand or collapse this section $\dfrac{7x + 17}{(x + 3)^2} = \dfrac{A}{x + 3} + \dfrac{B}{(x + 3)^2}$ $7x + 17 = A(x + 3) + B$ Set x = -3 $7(-3) + 17 = A(-3 + 3) + B$ $B = -4$ Equate the constant terms $17 = 3A + B$ $17 = 3A - 4$ $A = 7$ Log in or register to post comments
Solution Click here to… Jhun Vert Fri, 06/07/2024 - 19:05 Solution Click here to expand or collapse this section $\dfrac{7x + 17}{(x + 3)^2} = \dfrac{A}{x + 3} + \dfrac{B}{(x + 3)^2}$ $7x + 17 = A(x + 3) + B$ Set x = -3 $7(-3) + 17 = A(-3 + 3) + B$ $B = -4$ Equate the constant terms $17 = 3A + B$ $17 = 3A - 4$ $A = 7$ Log in or register to post comments
Solution Click here to…