Solve for D in the given partial fraction:$$ \dfrac{4x^2 + 7x + 8}{x(x + 2)^3} = \dfrac{A}{x} + \dfrac{B}{x + 2} + \dfrac{C}{(x + 2)^2} + \dfrac{D}{(x + 2)^3} $$ | MATHalino

Solve for D in the given partial fraction:

$$ \dfrac{4x^2 + 7x + 8}{x(x + 2)^3} = \dfrac{A}{x} + \dfrac{B}{x + 2} + \dfrac{C}{(x + 2)^2} + \dfrac{D}{(x + 2)^3} $$

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