Solve for D in the given partial fraction:$$ \dfrac{4x^2 + 7x + 8}{x(x + 2)^3} = \dfrac{A}{x} + \dfrac{B}{x + 2} + \dfrac{C}{(x + 2)^2} + \dfrac{D}{(x + 2)^3} $$ Solve for D in the given partial fraction: $$ \dfrac{4x^2 + 7x + 8}{x(x + 2)^3} = \dfrac{A}{x} + \dfrac{B}{x + 2} + \dfrac{C}{(x + 2)^2} + \dfrac{D}{(x + 2)^3} $$ Log in or register to post comments
