Solution to Problem 638 | Deflection of Cantilever Beams

$EI \, t_{A/B} = (Area_{AB}) \, \bar{X}_A$

$EI \, t_{A/B} = 2(2)(3) - \frac{1}{2}(4)(1)(\frac{8}{3})$

$EI \, t_{A/B} = \frac{20}{3} = 6.67 \, \text{ kN}\cdot\text{m}^3$
 

∴   EIδ = 6.67 kN·m³ upward           answer