$A_1 = 6(1) = 6 \, \text{ in}^2$
$y_1 = 0.5 \, \text{ in}$
$A_2 = 8(1) = 8 \, \text{ in}^2$
$y_2 = 5 \, \text{ in}$
$A = A_1 + A_2 = 6 + 8$
$A = 14 \, \text{ in}^2$
$A \, \bar{y} = \Sigma ay$
$14 \, \bar{y} = 6(0.5) + 8(5)$
$y = 3.07 \, \text{ in}$ above the base answer