From
Equilibrium of Concurrent Force System, three coplanar forces in equilibrium are concurrent.
$\dfrac{y}{1} = \dfrac{2}{1}$
$y = 2 \, \text{ m}$
$\tan \theta_{Ax} = \dfrac{y}{3}$
$\tan \theta_{Ax} = \dfrac{2}{3}$
$\theta_{Ax} = 33.69^\circ$ okay
$\tan \theta_{Bx} = \dfrac{2}{1}$
$\theta_{Bx} = 63.43^\circ$
$\alpha = 90^\circ - \theta_{Ax} = 56.31^\circ$
$\beta = 90^\circ - \theta_{Bx} = 26.57^\circ$
$\phi = \theta_{Ax} + \theta_{Bx} = 97.12^\circ$
$\dfrac{R_A}{\sin \beta} = \dfrac{R_B}{\sin \alpha} = \dfrac{40}{\sin \phi}$
$\dfrac{R_A}{\sin 26.57^\circ} = \dfrac{R_B}{\sin 56.31^\circ} = \dfrac{40}{\sin 97.12^\circ}$
$R_A = 18.03 \, \text{ kN}$ okay
$R_B = 33.54 \, \text{ kN}$ okay