From pulley A
$\Sigma F_V = 0$
$3T_1 = 36 + 720$
$3T_1 = 726$
$T_1 = 252 \, \text{ kg}$
From pulley B
$\Sigma F_V = 0$
$3T_2 = 36 + T_1$
$3T_2 = 36 + 252$
$3T_2 = 288$
$T_2 = 96 \, \text{ kg}$
From pulley C
$P = T_2$
Thus, $P = 96 \, \text{ kg}$ answer