Problem 326 | Equilibrium of Force System

$\theta = 29.93^\circ$
 

From the FBD of 200 kN cylinder
$\Sigma F_V = 0$

$R_C \sin \theta = 200$

$R_C \sin 29.93^\circ = 200$

$R_C = 400.85 \, \text{ kN}$           answer
 

$\Sigma F_H = 0$

$R_D = R_C \cos \theta$

$R_D = 400.85 \cos 29.93^\circ$

$R_D = 347.39 \, \text{ kN}$           answer
 

From the FBD of 400 kN cylinder
$\Sigma F_H = 0$

$R_A = R_C \cos \theta$

$R_A = 400.85 \cos 29.93^\circ$

$R_A = 347.39 \, \text{ kN}$           answer
 

$\Sigma F_V = 0$

$R_B = 400 + R_C \sin \theta$

$R_B = 400 + 400.85 \sin 29.93^\circ$

$R_B = 600 \, \text{ kN}$           answer