Problem 01 Radium decomposes at a rate proportional to the quantity of radium present. Suppose it is found that in 25 years approximately 1.1% of certain quantity of radium has decomposed. Determine how long (in years) it will take for one-half of the original amount of radium to decompose.

Solution 01

$x = x_oe^{-kt}$

When t = 25 yrs., x = (100% - 1.1%)x_{o} = 0.989x_{o} $0.989x_o = x_oe^{-25k}$

$e^{-k} = 0.989^{1/25}$

Thus, $x = 0.989^{t/25}x_o$

When x = 0.5x_{o} $0.5x_o = 0.989^{t/25}x_o$

$0.5^{25} = 0.989^t$

$t = \dfrac{25 \ln 0.5}{\ln 0.989}$

$t = 1566.65 ~ \text{yrs}$ answer

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