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46 | 86 | By inzenyrp 8 months 2 weeks ago |

find the general solution
2y ln y dx - x (1 + 2x ln y) dy = 0
a soccer ball with mass 0.420 kg is initially moving with speed 2.00 m/s. a soccer player kicks the ball, exerting a constant force of magnitude 40.0 N in the same direction as the ball's motion. over what distance must the player's foot be in contact with the ball to increase the ball's speed to 6.00 m/s?
tdx/dx = 6t(e^ 2t) +x(2t-1)
y' = (x + xy^2)/4y
Please help me solve this one!


Good day,
I got stuck finding the manual solution for this problem without relying to the solve function of Casio calculator
The original equation was
[(1+x)40] -1 = (181205.95/3000)x
Then I tried using properties of logarithm and I simplified it to this equation:
[ln(181205.95/3000)]/40 = ln(1+x) - (1/40)[ln(x+3000/181205.95)]
0.102526 = ln(x+1) - 0.025ln(x+0.0165557)
Answer: x = 0.02
17. At what speed must a 1000kg car approach a ramp which has a slope and 12m high at the top such that it will just coast to the top. Assume the constant retarding force due to friction, wind, etc. to be 60kg.

1434 (fl. singer 4th edition)
Determine the maximum torque that can be applied at 1.0 m from the right end of the shaft, without causing excessive rotation.
May answer key po ba kayo nito. Icheck ko lang po sana kung tama answers ko. Thank you po. Critical points/maxima and minima
y=4-6x+x²
y=(2x-1)²
y=2+12x-x³
y=x³-3x²-9x+20
y=x³-3x²+4x+5
y=x³-6x²+12x
y=x⁴+2x²+8x+3
y=16x+4x²-x⁴
y=x²(x-2)²
a³y=x⁴
9a³y=x(4a-x)³
a³y=x²(2a²-x²)
a³y=x³(4a-3x)
a⁵y=x⁴(3a²-2x²)
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