By binomial distribution,… Infinitesimal Sat, 05/02/2020 - 12:49 pm By binomial distribution, the probability is $1 - \displaystyle{\sum_{n=951}^{1000} \left(\dfrac{1}{10}\right)^n \left(\dfrac{9}{10} \right)^{1000-n}}$ 0 likes Log in or register to post comments

## By binomial distribution,…

By binomial distribution, the probability is

$1 - \displaystyle{\sum_{n=951}^{1000} \left(\dfrac{1}{10}\right)^n \left(\dfrac{9}{10} \right)^{1000-n}}$