# Linear Differential Equations

Submitted by agentcollins on September 4, 2016 - 7:49pm

Please help. I need it asap.

Solve the linear differential equation:

(D5–12D4+52D3–112D2+192D–256)y = 0

When I factored it out. I got (D-4)^3 (D^2 +4)

With D-4..

My equation will be Y= (C1 + C2x + C3x^2)e^4x

But how about my D^2 + 4?

How can I add that in my equation?

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## D^2 +4 will actually be $C_4

D^2 +4 will actually be $C_4 \cos 2x + C_5 \sin 2x$

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