Curvature and Radius of Curvature

Curvature (symbol, $\kappa$) is the mathematical expression of how much a curve actually curved. It is the measure of the average change in direction of the curve per unit of arc. Imagine a particle to move along the circle from point 1 to point 2, the higher the number of $\kappa$, the more quickly the particle changes in direction. This quick change in direction is apparent in smaller circles.
 

Circle of Curvature

 

$\Delta s = \rho \cdot \Delta \alpha$

$\dfrac{1}{\rho} = \dfrac{\Delta \alpha}{\Delta s}$   ←   the curvature
 

Let 1/ρ = κ
$\kappa = \dfrac{\Delta \alpha}{\Delta s}$
 

It is important to note that curvature κ is reciprocal to the radius of curvature ρ according to the above equations.

$\kappa = \dfrac{1}{\rho}$

 

Curvature02.jpg

 

As P2 approaches P1, the ratio Δα/Δs approaches a limit. This limit is the curvature of the curve at a particular point, and from the above figure that point is P1.
$\displaystyle \kappa = \lim_{\Delta s \to 0}\dfrac{\Delta \alpha}{\Delta s}$

$\kappa = \dfrac{da}{ds}$
 

Curvature in xy-Plane
In a circle, κ is constant, however, if the curve in question is not a circle, κ represents the average curvature of the arc at a particular point.
 

From Analytic Geometry, the slope of the line m is equal to the tangent of angle of inclination, or m = tan α. Note that in Calculus, m = dy/dx.
$\tan \alpha = y'$

$\alpha = \arctan y'$
 

Differentiate both sides with respect to x:
$d\alpha = \dfrac{y'' \, dx}{1 + (y')^2}$
 

Note that the Differential Length of Arc in the xy-plane is given by this formula:
$ds = \sqrt{1 + (y')^2} \, dx$
 

Hence,
$\kappa = \dfrac{da}{ds} = \dfrac{\dfrac{y'' \, dx}{1 + (y')^2}}{\sqrt{1 + (y')^2} \, dx}$
 

Simplify the equation above, and we have this formula for Curvature:

$\kappa = \dfrac{y''}{\left[ 1 + (y')^2 \right]^{3/2}}$

 

And for the Radius of Curvature:

$\rho = \dfrac{\left[ 1 + (y')^2 \right]^{3/2}}{\left| y'' \right| }$

 

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